The rewrite relation of the following TRS is considered.
| a(x1) | → | b(x1) | (1) |
| a(b(b(x1))) | → | c(x1) | (2) |
| a(c(x1)) | → | c(b(a(a(x1)))) | (3) |
| a(x1) | → | b(x1) | (1) |
| b(b(a(x1))) | → | c(x1) | (4) |
| c(a(x1)) | → | a(a(b(c(x1)))) | (5) |
| a#(x1) | → | b#(x1) | (6) |
| b#(b(a(x1))) | → | c#(x1) | (7) |
| c#(a(x1)) | → | c#(x1) | (8) |
| c#(a(x1)) | → | b#(c(x1)) | (9) |
| c#(a(x1)) | → | a#(b(c(x1))) | (10) |
| c#(a(x1)) | → | a#(a(b(c(x1)))) | (11) |
| [b#(x1)] | = |
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| [b(x1)] | = |
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| [a#(x1)] | = |
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| [c#(x1)] | = |
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| [a(x1)] | = |
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| [c(x1)] | = |
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| a(x1) | → | b(x1) | (1) |
| b(b(a(x1))) | → | c(x1) | (4) |
| c(a(x1)) | → | a(a(b(c(x1)))) | (5) |
| c#(a(x1)) | → | a#(b(c(x1))) | (10) |
| [b#(x1)] | = |
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| [b(x1)] | = |
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| [a#(x1)] | = |
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| [c#(x1)] | = |
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| [a(x1)] | = |
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| [c(x1)] | = |
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| a(x1) | → | b(x1) | (1) |
| b(b(a(x1))) | → | c(x1) | (4) |
| c(a(x1)) | → | a(a(b(c(x1)))) | (5) |
| c#(a(x1)) | → | c#(x1) | (8) |
| c#(a(x1)) | → | b#(c(x1)) | (9) |
| [b#(x1)] | = |
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| [b(x1)] | = |
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| [a#(x1)] | = |
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| [c#(x1)] | = |
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| [a(x1)] | = |
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| [c(x1)] | = |
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| a(x1) | → | b(x1) | (1) |
| b(b(a(x1))) | → | c(x1) | (4) |
| c(a(x1)) | → | a(a(b(c(x1)))) | (5) |
| b#(b(a(x1))) | → | c#(x1) | (7) |
The dependency pairs are split into 0 components.