Certification Problem

Input (TPDB SRS_Standard/Trafo_06/hom01)

The rewrite relation of the following TRS is considered.

a(a(b(d(b(d(a(x1))))))) → a(a(c(a(a(b(d(x1))))))) (1)
a(a(c(x1))) → c(c(a(a(x1)))) (2)
c(c(c(x1))) → b(d(c(b(d(x1))))) (3)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
a(d(b(d(b(a(a(x1))))))) → d(b(a(a(c(a(a(x1))))))) (4)
c(a(a(x1))) → a(a(c(c(x1)))) (5)
c(c(c(x1))) → d(b(c(d(b(x1))))) (6)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
c#(c(c(x1))) → c#(d(b(x1))) (7)
c#(a(a(x1))) → c#(x1) (8)
c#(a(a(x1))) → c#(c(x1)) (9)
c#(a(a(x1))) → a#(c(c(x1))) (10)
c#(a(a(x1))) → a#(a(c(c(x1)))) (11)
a#(d(b(d(b(a(a(x1))))))) → c#(a(a(x1))) (12)
a#(d(b(d(b(a(a(x1))))))) → a#(c(a(a(x1)))) (13)
a#(d(b(d(b(a(a(x1))))))) → a#(a(c(a(a(x1))))) (14)

1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.