Certification Problem

Input (TPDB SRS_Standard/Secret_07_SRS/x04)

The rewrite relation of the following TRS is considered.

a(a(x1)) → a(b(a(b(a(x1))))) (1)
c(a(x1)) → a(b(a(a(c(x1))))) (2)
b(b(b(x1))) → a(b(x1)) (3)
c(b(x1)) → a(a(c(x1))) (4)
c(b(x1)) → b(a(d(x1))) (5)
d(d(x1)) → d(b(d(b(d(x1))))) (6)
c(c(x1)) → c(d(c(x1))) (7)
a(a(a(x1))) → a(b(b(x1))) (8)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Rule Removal

Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[d(x1)] = x1 +
0
[c(x1)] = x1 +
1
[b(x1)] = x1 +
0
[a(x1)] = x1 +
0
all of the following rules can be deleted.
c(b(x1)) → b(a(d(x1))) (5)

1.1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
a(a(x1)) → a(b(a(b(a(x1))))) (1)
a(c(x1)) → c(a(a(b(a(x1))))) (9)
b(b(b(x1))) → b(a(x1)) (10)
b(c(x1)) → c(a(a(x1))) (11)
d(d(x1)) → d(b(d(b(d(x1))))) (6)
c(c(x1)) → c(d(c(x1))) (7)
a(a(a(x1))) → b(b(a(x1))) (12)

1.1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
d#(d(x1)) → d#(b(d(x1))) (13)
d#(d(x1)) → d#(b(d(b(d(x1))))) (14)
d#(d(x1)) → b#(d(x1)) (15)
d#(d(x1)) → b#(d(b(d(x1)))) (16)
c#(c(x1)) → d#(c(x1)) (17)
c#(c(x1)) → c#(d(c(x1))) (18)
b#(c(x1)) → c#(a(a(x1))) (19)
b#(c(x1)) → a#(x1) (20)
b#(c(x1)) → a#(a(x1)) (21)
b#(b(b(x1))) → b#(a(x1)) (22)
b#(b(b(x1))) → a#(x1) (23)
a#(c(x1)) → c#(a(a(b(a(x1))))) (24)
a#(c(x1)) → b#(a(x1)) (25)
a#(c(x1)) → a#(x1) (26)
a#(c(x1)) → a#(b(a(x1))) (27)
a#(c(x1)) → a#(a(b(a(x1)))) (28)
a#(a(x1)) → b#(a(x1)) (29)
a#(a(x1)) → b#(a(b(a(x1)))) (30)
a#(a(x1)) → a#(b(a(x1))) (31)
a#(a(x1)) → a#(b(a(b(a(x1))))) (32)
a#(a(a(x1))) → b#(b(a(x1))) (33)
a#(a(a(x1))) → b#(a(x1)) (34)

1.1.1.1 Monotonic Reduction Pair Processor with Usable Rules

Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[d(x1)] = x1 +
0
[c(x1)] = x1 +
3
[b(x1)] = x1 +
0
[a(x1)] = x1 +
0
[d#(x1)] = x1 +
1
[c#(x1)] = x1 +
2
[b#(x1)] = x1 +
0
[a#(x1)] = x1 +
0
together with the usable rules
a(a(x1)) → a(b(a(b(a(x1))))) (1)
a(c(x1)) → c(a(a(b(a(x1))))) (9)
b(b(b(x1))) → b(a(x1)) (10)
b(c(x1)) → c(a(a(x1))) (11)
d(d(x1)) → d(b(d(b(d(x1))))) (6)
c(c(x1)) → c(d(c(x1))) (7)
a(a(a(x1))) → b(b(a(x1))) (12)
(w.r.t. the implicit argument filter of the reduction pair), the pairs
d#(d(x1)) → b#(d(x1)) (15)
d#(d(x1)) → b#(d(b(d(x1)))) (16)
c#(c(x1)) → d#(c(x1)) (17)
b#(c(x1)) → c#(a(a(x1))) (19)
b#(c(x1)) → a#(x1) (20)
b#(c(x1)) → a#(a(x1)) (21)
a#(c(x1)) → c#(a(a(b(a(x1))))) (24)
a#(c(x1)) → b#(a(x1)) (25)
a#(c(x1)) → a#(x1) (26)
a#(c(x1)) → a#(b(a(x1))) (27)
a#(c(x1)) → a#(a(b(a(x1)))) (28)
and no rules could be deleted.

1.1.1.1.1 Dependency Graph Processor

The dependency pairs are split into 3 components.