Certification Problem

Input (TPDB SRS_Standard/Secret_07_SRS/x01)

The rewrite relation of the following TRS is considered.

a(x1) → b(b(x1)) (1)
c(b(x1)) → d(x1) (2)
e(b(x1)) → c(c(x1)) (3)
d(b(x1)) → b(f(x1)) (4)
f(x1) → a(e(x1)) (5)
c(x1) → x1 (6)
a(a(x1)) → f(x1) (7)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
f#(x1) → e#(x1) (8)
f#(x1) → a#(e(x1)) (9)
e#(b(x1)) → c#(x1) (10)
e#(b(x1)) → c#(c(x1)) (11)
d#(b(x1)) → f#(x1) (12)
c#(b(x1)) → d#(x1) (13)
a#(a(x1)) → f#(x1) (14)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.