Certification Problem

Input (TPDB SRS_Standard/Secret_06_SRS/secr9)

The rewrite relation of the following TRS is considered.

a(c(x1)) → c(b(c(c(a(x1))))) (1)
b(b(b(x1))) → c(b(x1)) (2)
d(d(x1)) → d(b(d(b(d(x1))))) (3)
a(a(x1)) → a(d(a(x1))) (4)
a(b(x1)) → c(c(a(x1))) (5)
c(c(x1)) → c(b(c(b(c(x1))))) (6)
c(c(c(x1))) → c(b(b(x1))) (7)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
d#(d(x1)) → d#(b(d(x1))) (8)
d#(d(x1)) → d#(b(d(b(d(x1))))) (9)
d#(d(x1)) → b#(d(x1)) (10)
d#(d(x1)) → b#(d(b(d(x1)))) (11)
c#(c(x1)) → c#(b(c(x1))) (12)
c#(c(x1)) → c#(b(c(b(c(x1))))) (13)
c#(c(x1)) → b#(c(x1)) (14)
c#(c(x1)) → b#(c(b(c(x1)))) (15)
c#(c(c(x1))) → c#(b(b(x1))) (16)
c#(c(c(x1))) → b#(x1) (17)
c#(c(c(x1))) → b#(b(x1)) (18)
b#(b(b(x1))) → c#(b(x1)) (19)
a#(c(x1)) → c#(c(a(x1))) (20)
a#(c(x1)) → c#(b(c(c(a(x1))))) (21)
a#(c(x1)) → c#(a(x1)) (22)
a#(c(x1)) → b#(c(c(a(x1)))) (23)
a#(c(x1)) → a#(x1) (24)
a#(b(x1)) → c#(c(a(x1))) (25)
a#(b(x1)) → c#(a(x1)) (26)
a#(b(x1)) → a#(x1) (27)
a#(a(x1)) → d#(a(x1)) (28)
a#(a(x1)) → a#(d(a(x1))) (29)

1.1 Monotonic Reduction Pair Processor with Usable Rules

Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[d(x1)] = x1 +
0
[c(x1)] = x1 +
0
[b(x1)] = x1 +
0
[a(x1)] = x1 +
0
[d#(x1)] = x1 +
1
[c#(x1)] = x1 +
0
[b#(x1)] = x1 +
0
[a#(x1)] = x1 +
2
together with the usable rules
a(c(x1)) → c(b(c(c(a(x1))))) (1)
b(b(b(x1))) → c(b(x1)) (2)
d(d(x1)) → d(b(d(b(d(x1))))) (3)
a(a(x1)) → a(d(a(x1))) (4)
a(b(x1)) → c(c(a(x1))) (5)
c(c(x1)) → c(b(c(b(c(x1))))) (6)
c(c(c(x1))) → c(b(b(x1))) (7)
(w.r.t. the implicit argument filter of the reduction pair), the pairs
d#(d(x1)) → b#(d(x1)) (10)
d#(d(x1)) → b#(d(b(d(x1)))) (11)
a#(c(x1)) → c#(c(a(x1))) (20)
a#(c(x1)) → c#(b(c(c(a(x1))))) (21)
a#(c(x1)) → c#(a(x1)) (22)
a#(c(x1)) → b#(c(c(a(x1)))) (23)
a#(b(x1)) → c#(c(a(x1))) (25)
a#(b(x1)) → c#(a(x1)) (26)
a#(a(x1)) → d#(a(x1)) (28)
and no rules could be deleted.

1.1.1 Dependency Graph Processor

The dependency pairs are split into 3 components.