Certification Problem

Input (TPDB SRS_Standard/Secret_06_SRS/7)

The rewrite relation of the following TRS is considered.

a(b(b(x1))) → b(a(a(a(x1)))) (1)
a(a(b(x1))) → b(a(b(x1))) (2)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Closure Under Flat Contexts

Using the flat contexts

{b(☐), a(☐)}

We obtain the transformed TRS
b(a(b(b(x1)))) → b(b(a(a(a(x1))))) (3)
b(a(a(b(x1)))) → b(b(a(b(x1)))) (4)
a(a(b(b(x1)))) → a(b(a(a(a(x1))))) (5)
a(a(a(b(x1)))) → a(b(a(b(x1)))) (6)

1.1 Semantic Labeling

The following interpretations form a model of the rules.

As carrier we take the set {0,1}. Symbols are labeled by the interpretation of their arguments using the interpretations (modulo 2):

[b(x1)] = 2x1 + 0
[a(x1)] = 2x1 + 1

We obtain the labeled TRS
a1(a0(b0(b1(x1)))) → a0(b1(a1(a1(a1(x1))))) (7)
a1(a0(b0(b0(x1)))) → a0(b1(a1(a1(a0(x1))))) (8)
b1(a0(b0(b1(x1)))) → b0(b1(a1(a1(a1(x1))))) (9)
b1(a0(b0(b0(x1)))) → b0(b1(a1(a1(a0(x1))))) (10)
a1(a1(a0(b1(x1)))) → a0(b1(a0(b1(x1)))) (11)
a1(a1(a0(b0(x1)))) → a0(b1(a0(b0(x1)))) (12)
b1(a1(a0(b1(x1)))) → b0(b1(a0(b1(x1)))) (13)
b1(a1(a0(b0(x1)))) → b0(b1(a0(b0(x1)))) (14)

1.1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
b1#(a0(b0(b0(x1)))) → b1#(a1(a1(a0(x1)))) (15)
b1#(a0(b0(b0(x1)))) → a1#(a0(x1)) (16)
b1#(a0(b0(b0(x1)))) → a1#(a1(a0(x1))) (17)
b1#(a0(b0(b1(x1)))) → b1#(a1(a1(a1(x1)))) (18)
b1#(a0(b0(b1(x1)))) → a1#(x1) (19)
b1#(a0(b0(b1(x1)))) → a1#(a1(x1)) (20)
b1#(a0(b0(b1(x1)))) → a1#(a1(a1(x1))) (21)
b1#(a1(a0(b0(x1)))) → b1#(a0(b0(x1))) (22)
b1#(a1(a0(b1(x1)))) → b1#(a0(b1(x1))) (23)
a1#(a0(b0(b0(x1)))) → b1#(a1(a1(a0(x1)))) (24)
a1#(a0(b0(b0(x1)))) → a1#(a0(x1)) (25)
a1#(a0(b0(b0(x1)))) → a1#(a1(a0(x1))) (26)
a1#(a0(b0(b1(x1)))) → b1#(a1(a1(a1(x1)))) (27)
a1#(a0(b0(b1(x1)))) → a1#(x1) (28)
a1#(a0(b0(b1(x1)))) → a1#(a1(x1)) (29)
a1#(a0(b0(b1(x1)))) → a1#(a1(a1(x1))) (30)
a1#(a1(a0(b0(x1)))) → b1#(a0(b0(x1))) (31)
a1#(a1(a0(b1(x1)))) → b1#(a0(b1(x1))) (32)

1.1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.