Certification Problem

Input (TPDB SRS_Standard/Zantema_06/beans4)

The rewrite relation of the following TRS is considered.

b(a(a(x1))) → a(b(c(x1))) (1)
c(a(x1)) → a(c(x1)) (2)
b(c(a(x1))) → a(b(c(x1))) (3)
c(b(x1)) → b(a(x1)) (4)
a(c(b(x1))) → c(b(a(x1))) (5)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
c#(a(x1)) → c#(x1) (6)
b#(c(a(x1))) → a#(b(c(x1))) (7)
c#(b(x1)) → a#(x1) (8)
b#(a(a(x1))) → a#(b(c(x1))) (9)
b#(a(a(x1))) → c#(x1) (10)
c#(b(x1)) → b#(a(x1)) (11)
b#(c(a(x1))) → b#(c(x1)) (12)
b#(a(a(x1))) → b#(c(x1)) (13)
a#(c(b(x1))) → a#(x1) (14)
a#(c(b(x1))) → c#(b(a(x1))) (15)
c#(a(x1)) → a#(c(x1)) (16)
b#(c(a(x1))) → c#(x1) (17)
a#(c(b(x1))) → b#(a(x1)) (18)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.