The rewrite relation of the following TRS is considered.
| a(x1) | → | x1 | (1) |
| a(x1) | → | b(b(c(x1))) | (2) |
| a(c(b(x1))) | → | c(a(a(x1))) | (3) |
| c(x1) | → | x1 | (4) |
| a(x1) | → | x1 | (1) |
| a(x1) | → | c(b(b(x1))) | (5) |
| b(c(a(x1))) | → | a(a(c(x1))) | (6) |
| c(x1) | → | x1 | (4) |
| a#(x1) | → | c#(b(b(x1))) | (7) |
| a#(x1) | → | b#(b(x1)) | (8) |
| a#(x1) | → | b#(x1) | (9) |
| b#(c(a(x1))) | → | a#(a(c(x1))) | (10) |
| b#(c(a(x1))) | → | a#(c(x1)) | (11) |
| b#(c(a(x1))) | → | c#(x1) | (12) |
The dependency pairs are split into 1 component.
| a#(x1) | → | b#(b(x1)) | (8) |
| b#(c(a(x1))) | → | a#(a(c(x1))) | (10) |
| a#(x1) | → | b#(x1) | (9) |
| b#(c(a(x1))) | → | a#(c(x1)) | (11) |
| [a#(x1)] | = |
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| [b#(x1)] | = |
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| [b(x1)] | = |
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| [c(x1)] | = |
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| [a(x1)] | = |
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| b#(c(a(x1))) | → | a#(c(x1)) | (11) |
| [a#(x1)] | = |
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| [b#(x1)] | = |
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| [b(x1)] | = |
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| [c(x1)] | = |
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| [a(x1)] | = |
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| a#(x1) | → | b#(x1) | (9) |
| [a#(x1)] | = |
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| [b#(x1)] | = |
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| [b(x1)] | = |
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| [c(x1)] | = |
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| [a(x1)] | = |
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| a#(x1) | → | b#(b(x1)) | (8) |
| [a(x1)] | = | 1 · x1 |
| [c(x1)] | = | 1 · x1 |
| [b(x1)] | = | 1 · x1 |
| [b#(x1)] | = | 2 + 2 · x1 |
| [a#(x1)] | = | 2 · x1 |
| b#(c(a(x1))) | → | a#(a(c(x1))) | (10) |
There are no pairs anymore.