Certification Problem

Input (TPDB SRS_Relative/Waldmann_19/random-93)

The relative rewrite relation R/S is considered where R is the following TRS

c(a(b(x1))) → c(a(c(x1))) (1)
a(a(a(x1))) → c(a(a(x1))) (2)
a(b(a(x1))) → c(a(c(x1))) (3)
a(b(b(x1))) → a(c(b(x1))) (4)

and S is the following TRS.

b(c(c(x1))) → b(a(b(x1))) (5)
a(b(b(x1))) → a(a(c(x1))) (6)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
b(a(c(x1))) → c(a(c(x1))) (7)
a(a(a(x1))) → a(a(c(x1))) (8)
a(b(a(x1))) → c(a(c(x1))) (3)
b(b(a(x1))) → b(c(a(x1))) (9)
c(c(b(x1))) → b(a(b(x1))) (10)
b(b(a(x1))) → c(a(a(x1))) (11)

1.1 Closure Under Flat Contexts

Using the flat contexts

{b(☐), a(☐), c(☐)}

We obtain the transformed TRS
a(a(a(x1))) → a(a(c(x1))) (8)
b(b(a(x1))) → b(c(a(x1))) (9)
b(b(a(c(x1)))) → b(c(a(c(x1)))) (12)
a(b(a(c(x1)))) → a(c(a(c(x1)))) (13)
c(b(a(c(x1)))) → c(c(a(c(x1)))) (14)
b(a(b(a(x1)))) → b(c(a(c(x1)))) (15)
a(a(b(a(x1)))) → a(c(a(c(x1)))) (16)
c(a(b(a(x1)))) → c(c(a(c(x1)))) (17)
b(c(c(b(x1)))) → b(b(a(b(x1)))) (18)
a(c(c(b(x1)))) → a(b(a(b(x1)))) (19)
c(c(c(b(x1)))) → c(b(a(b(x1)))) (20)
b(b(b(a(x1)))) → b(c(a(a(x1)))) (21)
a(b(b(a(x1)))) → a(c(a(a(x1)))) (22)
c(b(b(a(x1)))) → c(c(a(a(x1)))) (23)

1.1.1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
aa(aa(aa(x1))) → aa(ac(ca(x1))) (24)
aa(aa(ac(x1))) → aa(ac(cc(x1))) (25)
aa(aa(ab(x1))) → aa(ac(cb(x1))) (26)
bb(ba(aa(x1))) → bc(ca(aa(x1))) (27)
bb(ba(ac(x1))) → bc(ca(ac(x1))) (28)
bb(ba(ab(x1))) → bc(ca(ab(x1))) (29)
bb(ba(ac(ca(x1)))) → bc(ca(ac(ca(x1)))) (30)
bb(ba(ac(cc(x1)))) → bc(ca(ac(cc(x1)))) (31)
bb(ba(ac(cb(x1)))) → bc(ca(ac(cb(x1)))) (32)
ab(ba(ac(ca(x1)))) → ac(ca(ac(ca(x1)))) (33)
ab(ba(ac(cc(x1)))) → ac(ca(ac(cc(x1)))) (34)
ab(ba(ac(cb(x1)))) → ac(ca(ac(cb(x1)))) (35)
cb(ba(ac(ca(x1)))) → cc(ca(ac(ca(x1)))) (36)
cb(ba(ac(cc(x1)))) → cc(ca(ac(cc(x1)))) (37)
cb(ba(ac(cb(x1)))) → cc(ca(ac(cb(x1)))) (38)
ba(ab(ba(aa(x1)))) → bc(ca(ac(ca(x1)))) (39)
ba(ab(ba(ac(x1)))) → bc(ca(ac(cc(x1)))) (40)
ba(ab(ba(ab(x1)))) → bc(ca(ac(cb(x1)))) (41)
aa(ab(ba(aa(x1)))) → ac(ca(ac(ca(x1)))) (42)
aa(ab(ba(ac(x1)))) → ac(ca(ac(cc(x1)))) (43)
aa(ab(ba(ab(x1)))) → ac(ca(ac(cb(x1)))) (44)
ca(ab(ba(aa(x1)))) → cc(ca(ac(ca(x1)))) (45)
ca(ab(ba(ac(x1)))) → cc(ca(ac(cc(x1)))) (46)
ca(ab(ba(ab(x1)))) → cc(ca(ac(cb(x1)))) (47)
bc(cc(cb(ba(x1)))) → bb(ba(ab(ba(x1)))) (48)
bc(cc(cb(bc(x1)))) → bb(ba(ab(bc(x1)))) (49)
bc(cc(cb(bb(x1)))) → bb(ba(ab(bb(x1)))) (50)
ac(cc(cb(ba(x1)))) → ab(ba(ab(ba(x1)))) (51)
ac(cc(cb(bc(x1)))) → ab(ba(ab(bc(x1)))) (52)
ac(cc(cb(bb(x1)))) → ab(ba(ab(bb(x1)))) (53)
cc(cc(cb(ba(x1)))) → cb(ba(ab(ba(x1)))) (54)
cc(cc(cb(bc(x1)))) → cb(ba(ab(bc(x1)))) (55)
cc(cc(cb(bb(x1)))) → cb(ba(ab(bb(x1)))) (56)
bb(bb(ba(aa(x1)))) → bc(ca(aa(aa(x1)))) (57)
bb(bb(ba(ac(x1)))) → bc(ca(aa(ac(x1)))) (58)
bb(bb(ba(ab(x1)))) → bc(ca(aa(ab(x1)))) (59)
ab(bb(ba(aa(x1)))) → ac(ca(aa(aa(x1)))) (60)
ab(bb(ba(ac(x1)))) → ac(ca(aa(ac(x1)))) (61)
ab(bb(ba(ab(x1)))) → ac(ca(aa(ab(x1)))) (62)
cb(bb(ba(aa(x1)))) → cc(ca(aa(aa(x1)))) (63)
cb(bb(ba(ac(x1)))) → cc(ca(aa(ac(x1)))) (64)
cb(bb(ba(ab(x1)))) → cc(ca(aa(ab(x1)))) (65)

1.1.1.1 Rule Removal

Using the linear polynomial interpretation over the naturals
[aa(x1)] = 1 + 1 · x1
[ac(x1)] = 1 + 1 · x1
[ca(x1)] = 1 · x1
[cc(x1)] = 1 + 1 · x1
[ab(x1)] = 1 + 1 · x1
[cb(x1)] = 1 + 1 · x1
[bb(x1)] = 1 · x1
[ba(x1)] = 1 + 1 · x1
[bc(x1)] = 1 · x1
all of the following rules can be deleted.
aa(aa(aa(x1))) → aa(ac(ca(x1))) (24)
bb(ba(aa(x1))) → bc(ca(aa(x1))) (27)
bb(ba(ac(x1))) → bc(ca(ac(x1))) (28)
bb(ba(ab(x1))) → bc(ca(ab(x1))) (29)
bb(ba(ac(ca(x1)))) → bc(ca(ac(ca(x1)))) (30)
bb(ba(ac(cc(x1)))) → bc(ca(ac(cc(x1)))) (31)
bb(ba(ac(cb(x1)))) → bc(ca(ac(cb(x1)))) (32)
ab(ba(ac(ca(x1)))) → ac(ca(ac(ca(x1)))) (33)
ab(ba(ac(cc(x1)))) → ac(ca(ac(cc(x1)))) (34)
ab(ba(ac(cb(x1)))) → ac(ca(ac(cb(x1)))) (35)
cb(ba(ac(ca(x1)))) → cc(ca(ac(ca(x1)))) (36)
cb(ba(ac(cc(x1)))) → cc(ca(ac(cc(x1)))) (37)
cb(ba(ac(cb(x1)))) → cc(ca(ac(cb(x1)))) (38)
ba(ab(ba(aa(x1)))) → bc(ca(ac(ca(x1)))) (39)
ba(ab(ba(ac(x1)))) → bc(ca(ac(cc(x1)))) (40)
ba(ab(ba(ab(x1)))) → bc(ca(ac(cb(x1)))) (41)
aa(ab(ba(aa(x1)))) → ac(ca(ac(ca(x1)))) (42)
aa(ab(ba(ac(x1)))) → ac(ca(ac(cc(x1)))) (43)
aa(ab(ba(ab(x1)))) → ac(ca(ac(cb(x1)))) (44)
ca(ab(ba(aa(x1)))) → cc(ca(ac(ca(x1)))) (45)

1.1.1.1.1 Rule Removal

Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions
prec(aa) = 1 weight(aa) = 5
prec(ac) = 4 weight(ac) = 5
prec(cc) = 2 weight(cc) = 4
prec(ab) = 3 weight(ab) = 7
prec(cb) = 0 weight(cb) = 6
prec(ca) = 5 weight(ca) = 5
prec(ba) = 6 weight(ba) = 1
prec(bc) = 7 weight(bc) = 7
prec(bb) = 8 weight(bb) = 8
all of the following rules can be deleted.
aa(aa(ac(x1))) → aa(ac(cc(x1))) (25)
aa(aa(ab(x1))) → aa(ac(cb(x1))) (26)
ca(ab(ba(ac(x1)))) → cc(ca(ac(cc(x1)))) (46)
ca(ab(ba(ab(x1)))) → cc(ca(ac(cb(x1)))) (47)
bc(cc(cb(ba(x1)))) → bb(ba(ab(ba(x1)))) (48)
bc(cc(cb(bc(x1)))) → bb(ba(ab(bc(x1)))) (49)
bc(cc(cb(bb(x1)))) → bb(ba(ab(bb(x1)))) (50)
ac(cc(cb(ba(x1)))) → ab(ba(ab(ba(x1)))) (51)
ac(cc(cb(bc(x1)))) → ab(ba(ab(bc(x1)))) (52)
ac(cc(cb(bb(x1)))) → ab(ba(ab(bb(x1)))) (53)
cc(cc(cb(ba(x1)))) → cb(ba(ab(ba(x1)))) (54)
cc(cc(cb(bc(x1)))) → cb(ba(ab(bc(x1)))) (55)
cc(cc(cb(bb(x1)))) → cb(ba(ab(bb(x1)))) (56)
bb(bb(ba(aa(x1)))) → bc(ca(aa(aa(x1)))) (57)
bb(bb(ba(ac(x1)))) → bc(ca(aa(ac(x1)))) (58)
bb(bb(ba(ab(x1)))) → bc(ca(aa(ab(x1)))) (59)
ab(bb(ba(aa(x1)))) → ac(ca(aa(aa(x1)))) (60)
ab(bb(ba(ac(x1)))) → ac(ca(aa(ac(x1)))) (61)
ab(bb(ba(ab(x1)))) → ac(ca(aa(ab(x1)))) (62)
cb(bb(ba(aa(x1)))) → cc(ca(aa(aa(x1)))) (63)
cb(bb(ba(ac(x1)))) → cc(ca(aa(ac(x1)))) (64)
cb(bb(ba(ab(x1)))) → cc(ca(aa(ab(x1)))) (65)

1.1.1.1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.