Certification Problem

Input (TPDB SRS_Relative/Waldmann_19/random-57)

The relative rewrite relation R/S is considered where R is the following TRS

a(a(b(x1))) → a(c(c(x1))) (1)
c(c(b(x1))) → b(b(c(x1))) (2)
c(a(a(x1))) → c(a(c(x1))) (3)

and S is the following TRS.

b(b(c(x1))) → b(a(c(x1))) (4)
c(a(c(x1))) → c(b(a(x1))) (5)
a(a(b(x1))) → a(a(b(x1))) (6)
a(b(a(x1))) → a(b(c(x1))) (7)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
b(a(a(x1))) → c(c(a(x1))) (8)
b(c(c(x1))) → c(b(b(x1))) (9)
a(a(c(x1))) → c(a(c(x1))) (10)
c(b(b(x1))) → c(a(b(x1))) (11)
c(a(c(x1))) → a(b(c(x1))) (12)
a(b(a(x1))) → c(b(a(x1))) (13)

1.1 Closure Under Flat Contexts

Using the flat contexts

{b(☐), a(☐), c(☐)}

We obtain the transformed TRS
b(b(a(a(x1)))) → b(c(c(a(x1)))) (14)
a(b(a(a(x1)))) → a(c(c(a(x1)))) (15)
c(b(a(a(x1)))) → c(c(c(a(x1)))) (16)
b(b(c(c(x1)))) → b(c(b(b(x1)))) (17)
a(b(c(c(x1)))) → a(c(b(b(x1)))) (18)
c(b(c(c(x1)))) → c(c(b(b(x1)))) (19)
b(a(a(c(x1)))) → b(c(a(c(x1)))) (20)
a(a(a(c(x1)))) → a(c(a(c(x1)))) (21)
c(a(a(c(x1)))) → c(c(a(c(x1)))) (22)
c(b(b(x1))) → c(a(b(x1))) (11)
b(c(a(c(x1)))) → b(a(b(c(x1)))) (23)
a(c(a(c(x1)))) → a(a(b(c(x1)))) (24)
c(c(a(c(x1)))) → c(a(b(c(x1)))) (25)
b(a(b(a(x1)))) → b(c(b(a(x1)))) (26)
a(a(b(a(x1)))) → a(c(b(a(x1)))) (27)
c(a(b(a(x1)))) → c(c(b(a(x1)))) (28)

1.1.1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
bb(ba(aa(ab(x1)))) → bc(cc(ca(ab(x1)))) (29)
bb(ba(aa(aa(x1)))) → bc(cc(ca(aa(x1)))) (30)
bb(ba(aa(ac(x1)))) → bc(cc(ca(ac(x1)))) (31)
ab(ba(aa(ab(x1)))) → ac(cc(ca(ab(x1)))) (32)
ab(ba(aa(aa(x1)))) → ac(cc(ca(aa(x1)))) (33)
ab(ba(aa(ac(x1)))) → ac(cc(ca(ac(x1)))) (34)
cb(ba(aa(ab(x1)))) → cc(cc(ca(ab(x1)))) (35)
cb(ba(aa(aa(x1)))) → cc(cc(ca(aa(x1)))) (36)
cb(ba(aa(ac(x1)))) → cc(cc(ca(ac(x1)))) (37)
bb(bc(cc(cb(x1)))) → bc(cb(bb(bb(x1)))) (38)
bb(bc(cc(ca(x1)))) → bc(cb(bb(ba(x1)))) (39)
bb(bc(cc(cc(x1)))) → bc(cb(bb(bc(x1)))) (40)
ab(bc(cc(cb(x1)))) → ac(cb(bb(bb(x1)))) (41)
ab(bc(cc(ca(x1)))) → ac(cb(bb(ba(x1)))) (42)
ab(bc(cc(cc(x1)))) → ac(cb(bb(bc(x1)))) (43)
cb(bc(cc(cb(x1)))) → cc(cb(bb(bb(x1)))) (44)
cb(bc(cc(ca(x1)))) → cc(cb(bb(ba(x1)))) (45)
cb(bc(cc(cc(x1)))) → cc(cb(bb(bc(x1)))) (46)
ba(aa(ac(cb(x1)))) → bc(ca(ac(cb(x1)))) (47)
ba(aa(ac(ca(x1)))) → bc(ca(ac(ca(x1)))) (48)
ba(aa(ac(cc(x1)))) → bc(ca(ac(cc(x1)))) (49)
aa(aa(ac(cb(x1)))) → ac(ca(ac(cb(x1)))) (50)
aa(aa(ac(ca(x1)))) → ac(ca(ac(ca(x1)))) (51)
aa(aa(ac(cc(x1)))) → ac(ca(ac(cc(x1)))) (52)
ca(aa(ac(cb(x1)))) → cc(ca(ac(cb(x1)))) (53)
ca(aa(ac(ca(x1)))) → cc(ca(ac(ca(x1)))) (54)
ca(aa(ac(cc(x1)))) → cc(ca(ac(cc(x1)))) (55)
cb(bb(bb(x1))) → ca(ab(bb(x1))) (56)
cb(bb(ba(x1))) → ca(ab(ba(x1))) (57)
cb(bb(bc(x1))) → ca(ab(bc(x1))) (58)
bc(ca(ac(cb(x1)))) → ba(ab(bc(cb(x1)))) (59)
bc(ca(ac(ca(x1)))) → ba(ab(bc(ca(x1)))) (60)
bc(ca(ac(cc(x1)))) → ba(ab(bc(cc(x1)))) (61)
ac(ca(ac(cb(x1)))) → aa(ab(bc(cb(x1)))) (62)
ac(ca(ac(ca(x1)))) → aa(ab(bc(ca(x1)))) (63)
ac(ca(ac(cc(x1)))) → aa(ab(bc(cc(x1)))) (64)
cc(ca(ac(cb(x1)))) → ca(ab(bc(cb(x1)))) (65)
cc(ca(ac(ca(x1)))) → ca(ab(bc(ca(x1)))) (66)
cc(ca(ac(cc(x1)))) → ca(ab(bc(cc(x1)))) (67)
ba(ab(ba(ab(x1)))) → bc(cb(ba(ab(x1)))) (68)
ba(ab(ba(aa(x1)))) → bc(cb(ba(aa(x1)))) (69)
ba(ab(ba(ac(x1)))) → bc(cb(ba(ac(x1)))) (70)
aa(ab(ba(ab(x1)))) → ac(cb(ba(ab(x1)))) (71)
aa(ab(ba(aa(x1)))) → ac(cb(ba(aa(x1)))) (72)
aa(ab(ba(ac(x1)))) → ac(cb(ba(ac(x1)))) (73)
ca(ab(ba(ab(x1)))) → cc(cb(ba(ab(x1)))) (74)
ca(ab(ba(aa(x1)))) → cc(cb(ba(aa(x1)))) (75)
ca(ab(ba(ac(x1)))) → cc(cb(ba(ac(x1)))) (76)

1.1.1.1 Rule Removal

Using the matrix interpretations of dimension 2 with strict dimension 1 over the integers
[bb(x1)] =
0
1
+
1 0
0 0
· x1
[ba(x1)] =
1
0
+
1 0
0 0
· x1
[aa(x1)] =
2
0
+
1 0
0 0
· x1
[ab(x1)] =
0
0
+
1 0
0 0
· x1
[bc(x1)] =
0
0
+
1 0
0 0
· x1
[cc(x1)] =
1
0
+
1 0
0 0
· x1
[ca(x1)] =
2
0
+
1 0
0 0
· x1
[ac(x1)] =
0
0
+
1 0
0 0
· x1
[cb(x1)] =
1
0
+
1 1
0 0
· x1
all of the following rules can be deleted.
ba(aa(ac(cb(x1)))) → bc(ca(ac(cb(x1)))) (47)
ba(aa(ac(ca(x1)))) → bc(ca(ac(ca(x1)))) (48)
ba(aa(ac(cc(x1)))) → bc(ca(ac(cc(x1)))) (49)
aa(aa(ac(cb(x1)))) → ac(ca(ac(cb(x1)))) (50)
aa(aa(ac(ca(x1)))) → ac(ca(ac(ca(x1)))) (51)
aa(aa(ac(cc(x1)))) → ac(ca(ac(cc(x1)))) (52)
ca(aa(ac(cb(x1)))) → cc(ca(ac(cb(x1)))) (53)
ca(aa(ac(ca(x1)))) → cc(ca(ac(ca(x1)))) (54)
ca(aa(ac(cc(x1)))) → cc(ca(ac(cc(x1)))) (55)
bc(ca(ac(cb(x1)))) → ba(ab(bc(cb(x1)))) (59)
bc(ca(ac(ca(x1)))) → ba(ab(bc(ca(x1)))) (60)
bc(ca(ac(cc(x1)))) → ba(ab(bc(cc(x1)))) (61)
cc(ca(ac(cb(x1)))) → ca(ab(bc(cb(x1)))) (65)
cc(ca(ac(ca(x1)))) → ca(ab(bc(ca(x1)))) (66)
cc(ca(ac(cc(x1)))) → ca(ab(bc(cc(x1)))) (67)
aa(ab(ba(ab(x1)))) → ac(cb(ba(ab(x1)))) (71)
aa(ab(ba(aa(x1)))) → ac(cb(ba(aa(x1)))) (72)
aa(ab(ba(ac(x1)))) → ac(cb(ba(ac(x1)))) (73)

1.1.1.1.1 Rule Removal

Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions
prec(bb) = 7 weight(bb) = 4
prec(ba) = 2 weight(ba) = 3
prec(aa) = 4 weight(aa) = 4
prec(ab) = 6 weight(ab) = 5
prec(bc) = 0 weight(bc) = 2
prec(cc) = 1 weight(cc) = 4
prec(ca) = 3 weight(ca) = 5
prec(ac) = 5 weight(ac) = 3
prec(cb) = 8 weight(cb) = 6
all of the following rules can be deleted.
bb(ba(aa(ab(x1)))) → bc(cc(ca(ab(x1)))) (29)
bb(ba(aa(aa(x1)))) → bc(cc(ca(aa(x1)))) (30)
bb(ba(aa(ac(x1)))) → bc(cc(ca(ac(x1)))) (31)
ab(ba(aa(ab(x1)))) → ac(cc(ca(ab(x1)))) (32)
ab(ba(aa(aa(x1)))) → ac(cc(ca(aa(x1)))) (33)
ab(ba(aa(ac(x1)))) → ac(cc(ca(ac(x1)))) (34)
cb(ba(aa(ab(x1)))) → cc(cc(ca(ab(x1)))) (35)
cb(ba(aa(aa(x1)))) → cc(cc(ca(aa(x1)))) (36)
cb(ba(aa(ac(x1)))) → cc(cc(ca(ac(x1)))) (37)
bb(bc(cc(cb(x1)))) → bc(cb(bb(bb(x1)))) (38)
bb(bc(cc(ca(x1)))) → bc(cb(bb(ba(x1)))) (39)
bb(bc(cc(cc(x1)))) → bc(cb(bb(bc(x1)))) (40)
ab(bc(cc(cb(x1)))) → ac(cb(bb(bb(x1)))) (41)
ab(bc(cc(ca(x1)))) → ac(cb(bb(ba(x1)))) (42)
ab(bc(cc(cc(x1)))) → ac(cb(bb(bc(x1)))) (43)
cb(bc(cc(cb(x1)))) → cc(cb(bb(bb(x1)))) (44)
cb(bc(cc(ca(x1)))) → cc(cb(bb(ba(x1)))) (45)
cb(bc(cc(cc(x1)))) → cc(cb(bb(bc(x1)))) (46)
cb(bb(bb(x1))) → ca(ab(bb(x1))) (56)
cb(bb(ba(x1))) → ca(ab(ba(x1))) (57)
cb(bb(bc(x1))) → ca(ab(bc(x1))) (58)
ac(ca(ac(cb(x1)))) → aa(ab(bc(cb(x1)))) (62)
ac(ca(ac(ca(x1)))) → aa(ab(bc(ca(x1)))) (63)
ac(ca(ac(cc(x1)))) → aa(ab(bc(cc(x1)))) (64)
ba(ab(ba(ab(x1)))) → bc(cb(ba(ab(x1)))) (68)
ba(ab(ba(aa(x1)))) → bc(cb(ba(aa(x1)))) (69)
ba(ab(ba(ac(x1)))) → bc(cb(ba(ac(x1)))) (70)
ca(ab(ba(ab(x1)))) → cc(cb(ba(ab(x1)))) (74)
ca(ab(ba(aa(x1)))) → cc(cb(ba(aa(x1)))) (75)
ca(ab(ba(ac(x1)))) → cc(cb(ba(ac(x1)))) (76)

1.1.1.1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.