Certification Problem

Input (TPDB SRS_Relative/Waldmann_19/random-160)

The relative rewrite relation R/S is considered where R is the following TRS

b(b(b(x1))) → b(a(b(x1))) (1)
c(c(c(x1))) → c(b(a(x1))) (2)

and S is the following TRS.

b(a(c(x1))) → a(a(a(x1))) (3)
c(a(b(x1))) → a(c(c(x1))) (4)
a(b(c(x1))) → b(c(c(x1))) (5)
c(a(c(x1))) → a(c(a(x1))) (6)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
b(b(b(x1))) → b(a(b(x1))) (1)
c(c(c(x1))) → a(b(c(x1))) (7)
c(a(b(x1))) → a(a(a(x1))) (8)
b(a(c(x1))) → c(c(a(x1))) (9)
c(b(a(x1))) → c(c(b(x1))) (10)
c(a(c(x1))) → a(c(a(x1))) (6)

1.1 Closure Under Flat Contexts

Using the flat contexts

{b(☐), a(☐), c(☐)}

We obtain the transformed TRS
b(b(b(x1))) → b(a(b(x1))) (1)
b(c(c(c(x1)))) → b(a(b(c(x1)))) (11)
a(c(c(c(x1)))) → a(a(b(c(x1)))) (12)
c(c(c(c(x1)))) → c(a(b(c(x1)))) (13)
c(b(a(x1))) → c(c(b(x1))) (10)
b(c(a(b(x1)))) → b(a(a(a(x1)))) (14)
a(c(a(b(x1)))) → a(a(a(a(x1)))) (15)
c(c(a(b(x1)))) → c(a(a(a(x1)))) (16)
b(b(a(c(x1)))) → b(c(c(a(x1)))) (17)
a(b(a(c(x1)))) → a(c(c(a(x1)))) (18)
c(b(a(c(x1)))) → c(c(c(a(x1)))) (19)
b(c(a(c(x1)))) → b(a(c(a(x1)))) (20)
a(c(a(c(x1)))) → a(a(c(a(x1)))) (21)
c(c(a(c(x1)))) → c(a(c(a(x1)))) (22)

1.1.1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
bb(bb(bb(x1))) → ba(ab(bb(x1))) (23)
bb(bb(ba(x1))) → ba(ab(ba(x1))) (24)
bb(bb(bc(x1))) → ba(ab(bc(x1))) (25)
bc(cc(cc(cb(x1)))) → ba(ab(bc(cb(x1)))) (26)
bc(cc(cc(ca(x1)))) → ba(ab(bc(ca(x1)))) (27)
bc(cc(cc(cc(x1)))) → ba(ab(bc(cc(x1)))) (28)
ac(cc(cc(cb(x1)))) → aa(ab(bc(cb(x1)))) (29)
ac(cc(cc(ca(x1)))) → aa(ab(bc(ca(x1)))) (30)
ac(cc(cc(cc(x1)))) → aa(ab(bc(cc(x1)))) (31)
cc(cc(cc(cb(x1)))) → ca(ab(bc(cb(x1)))) (32)
cc(cc(cc(ca(x1)))) → ca(ab(bc(ca(x1)))) (33)
cc(cc(cc(cc(x1)))) → ca(ab(bc(cc(x1)))) (34)
cb(ba(ab(x1))) → cc(cb(bb(x1))) (35)
cb(ba(aa(x1))) → cc(cb(ba(x1))) (36)
cb(ba(ac(x1))) → cc(cb(bc(x1))) (37)
bc(ca(ab(bb(x1)))) → ba(aa(aa(ab(x1)))) (38)
bc(ca(ab(ba(x1)))) → ba(aa(aa(aa(x1)))) (39)
bc(ca(ab(bc(x1)))) → ba(aa(aa(ac(x1)))) (40)
ac(ca(ab(bb(x1)))) → aa(aa(aa(ab(x1)))) (41)
ac(ca(ab(ba(x1)))) → aa(aa(aa(aa(x1)))) (42)
ac(ca(ab(bc(x1)))) → aa(aa(aa(ac(x1)))) (43)
cc(ca(ab(bb(x1)))) → ca(aa(aa(ab(x1)))) (44)
cc(ca(ab(ba(x1)))) → ca(aa(aa(aa(x1)))) (45)
cc(ca(ab(bc(x1)))) → ca(aa(aa(ac(x1)))) (46)
bb(ba(ac(cb(x1)))) → bc(cc(ca(ab(x1)))) (47)
bb(ba(ac(ca(x1)))) → bc(cc(ca(aa(x1)))) (48)
bb(ba(ac(cc(x1)))) → bc(cc(ca(ac(x1)))) (49)
ab(ba(ac(cb(x1)))) → ac(cc(ca(ab(x1)))) (50)
ab(ba(ac(ca(x1)))) → ac(cc(ca(aa(x1)))) (51)
ab(ba(ac(cc(x1)))) → ac(cc(ca(ac(x1)))) (52)
cb(ba(ac(cb(x1)))) → cc(cc(ca(ab(x1)))) (53)
cb(ba(ac(ca(x1)))) → cc(cc(ca(aa(x1)))) (54)
cb(ba(ac(cc(x1)))) → cc(cc(ca(ac(x1)))) (55)
bc(ca(ac(cb(x1)))) → ba(ac(ca(ab(x1)))) (56)
bc(ca(ac(ca(x1)))) → ba(ac(ca(aa(x1)))) (57)
bc(ca(ac(cc(x1)))) → ba(ac(ca(ac(x1)))) (58)
ac(ca(ac(cb(x1)))) → aa(ac(ca(ab(x1)))) (59)
ac(ca(ac(ca(x1)))) → aa(ac(ca(aa(x1)))) (60)
ac(ca(ac(cc(x1)))) → aa(ac(ca(ac(x1)))) (61)
cc(ca(ac(cb(x1)))) → ca(ac(ca(ab(x1)))) (62)
cc(ca(ac(ca(x1)))) → ca(ac(ca(aa(x1)))) (63)
cc(ca(ac(cc(x1)))) → ca(ac(ca(ac(x1)))) (64)

1.1.1.1 Rule Removal

Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions
prec(bb) = 5 weight(bb) = 3
prec(ba) = 3 weight(ba) = 4
prec(ab) = 8 weight(ab) = 2
prec(bc) = 4 weight(bc) = 5
prec(cc) = 6 weight(cc) = 3
prec(cb) = 7 weight(cb) = 1
prec(ca) = 1 weight(ca) = 2
prec(ac) = 2 weight(ac) = 4
prec(aa) = 0 weight(aa) = 3
all of the following rules can be deleted.
bb(bb(bb(x1))) → ba(ab(bb(x1))) (23)
bb(bb(ba(x1))) → ba(ab(ba(x1))) (24)
bb(bb(bc(x1))) → ba(ab(bc(x1))) (25)
bc(cc(cc(cb(x1)))) → ba(ab(bc(cb(x1)))) (26)
bc(cc(cc(ca(x1)))) → ba(ab(bc(ca(x1)))) (27)
bc(cc(cc(cc(x1)))) → ba(ab(bc(cc(x1)))) (28)
ac(cc(cc(cb(x1)))) → aa(ab(bc(cb(x1)))) (29)
ac(cc(cc(ca(x1)))) → aa(ab(bc(ca(x1)))) (30)
ac(cc(cc(cc(x1)))) → aa(ab(bc(cc(x1)))) (31)
cc(cc(cc(cb(x1)))) → ca(ab(bc(cb(x1)))) (32)
cc(cc(cc(ca(x1)))) → ca(ab(bc(ca(x1)))) (33)
cc(cc(cc(cc(x1)))) → ca(ab(bc(cc(x1)))) (34)
cb(ba(ab(x1))) → cc(cb(bb(x1))) (35)
cb(ba(aa(x1))) → cc(cb(ba(x1))) (36)
cb(ba(ac(x1))) → cc(cb(bc(x1))) (37)
bc(ca(ab(bb(x1)))) → ba(aa(aa(ab(x1)))) (38)
bc(ca(ab(ba(x1)))) → ba(aa(aa(aa(x1)))) (39)
bc(ca(ab(bc(x1)))) → ba(aa(aa(ac(x1)))) (40)
ac(ca(ab(bb(x1)))) → aa(aa(aa(ab(x1)))) (41)
ac(ca(ab(ba(x1)))) → aa(aa(aa(aa(x1)))) (42)
ac(ca(ab(bc(x1)))) → aa(aa(aa(ac(x1)))) (43)
cc(ca(ab(bb(x1)))) → ca(aa(aa(ab(x1)))) (44)
cc(ca(ab(ba(x1)))) → ca(aa(aa(aa(x1)))) (45)
cc(ca(ab(bc(x1)))) → ca(aa(aa(ac(x1)))) (46)
bb(ba(ac(cb(x1)))) → bc(cc(ca(ab(x1)))) (47)
bb(ba(ac(ca(x1)))) → bc(cc(ca(aa(x1)))) (48)
bb(ba(ac(cc(x1)))) → bc(cc(ca(ac(x1)))) (49)
ab(ba(ac(cb(x1)))) → ac(cc(ca(ab(x1)))) (50)
ab(ba(ac(ca(x1)))) → ac(cc(ca(aa(x1)))) (51)
ab(ba(ac(cc(x1)))) → ac(cc(ca(ac(x1)))) (52)
cb(ba(ac(cb(x1)))) → cc(cc(ca(ab(x1)))) (53)
cb(ba(ac(ca(x1)))) → cc(cc(ca(aa(x1)))) (54)
cb(ba(ac(cc(x1)))) → cc(cc(ca(ac(x1)))) (55)
bc(ca(ac(cb(x1)))) → ba(ac(ca(ab(x1)))) (56)
bc(ca(ac(ca(x1)))) → ba(ac(ca(aa(x1)))) (57)
bc(ca(ac(cc(x1)))) → ba(ac(ca(ac(x1)))) (58)
ac(ca(ac(cb(x1)))) → aa(ac(ca(ab(x1)))) (59)
ac(ca(ac(ca(x1)))) → aa(ac(ca(aa(x1)))) (60)
ac(ca(ac(cc(x1)))) → aa(ac(ca(ac(x1)))) (61)
cc(ca(ac(cb(x1)))) → ca(ac(ca(ab(x1)))) (62)
cc(ca(ac(ca(x1)))) → ca(ac(ca(aa(x1)))) (63)
cc(ca(ac(cc(x1)))) → ca(ac(ca(ac(x1)))) (64)

1.1.1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.