Certification Problem

Input (TPDB SRS_Relative/Waldmann_19/random-140)

The relative rewrite relation R/S is considered where R is the following TRS

c(c(c(x1))) → a(a(c(x1))) (1)
b(a(a(x1))) → b(b(c(x1))) (2)
c(a(c(x1))) → a(c(c(x1))) (3)
b(c(c(x1))) → b(c(b(x1))) (4)

and S is the following TRS.

a(b(a(x1))) → a(c(c(x1))) (5)
a(a(b(x1))) → c(b(a(x1))) (6)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
c(c(c(x1))) → c(a(a(x1))) (7)
a(a(b(x1))) → c(b(b(x1))) (8)
c(a(c(x1))) → c(c(a(x1))) (9)
c(c(b(x1))) → b(c(b(x1))) (10)
a(b(a(x1))) → c(c(a(x1))) (11)
b(a(a(x1))) → a(b(c(x1))) (12)

1.1 Closure Under Flat Contexts

Using the flat contexts

{c(☐), a(☐), b(☐)}

We obtain the transformed TRS
c(c(c(x1))) → c(a(a(x1))) (7)
c(a(c(x1))) → c(c(a(x1))) (9)
c(a(a(b(x1)))) → c(c(b(b(x1)))) (13)
a(a(a(b(x1)))) → a(c(b(b(x1)))) (14)
b(a(a(b(x1)))) → b(c(b(b(x1)))) (15)
c(c(c(b(x1)))) → c(b(c(b(x1)))) (16)
a(c(c(b(x1)))) → a(b(c(b(x1)))) (17)
b(c(c(b(x1)))) → b(b(c(b(x1)))) (18)
c(a(b(a(x1)))) → c(c(c(a(x1)))) (19)
a(a(b(a(x1)))) → a(c(c(a(x1)))) (20)
b(a(b(a(x1)))) → b(c(c(a(x1)))) (21)
c(b(a(a(x1)))) → c(a(b(c(x1)))) (22)
a(b(a(a(x1)))) → a(a(b(c(x1)))) (23)
b(b(a(a(x1)))) → b(a(b(c(x1)))) (24)

1.1.1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
cc(cc(cc(x1))) → ca(aa(ac(x1))) (25)
cc(cc(ca(x1))) → ca(aa(aa(x1))) (26)
cc(cc(cb(x1))) → ca(aa(ab(x1))) (27)
ca(ac(cc(x1))) → cc(ca(ac(x1))) (28)
ca(ac(ca(x1))) → cc(ca(aa(x1))) (29)
ca(ac(cb(x1))) → cc(ca(ab(x1))) (30)
ca(aa(ab(bc(x1)))) → cc(cb(bb(bc(x1)))) (31)
ca(aa(ab(ba(x1)))) → cc(cb(bb(ba(x1)))) (32)
ca(aa(ab(bb(x1)))) → cc(cb(bb(bb(x1)))) (33)
aa(aa(ab(bc(x1)))) → ac(cb(bb(bc(x1)))) (34)
aa(aa(ab(ba(x1)))) → ac(cb(bb(ba(x1)))) (35)
aa(aa(ab(bb(x1)))) → ac(cb(bb(bb(x1)))) (36)
ba(aa(ab(bc(x1)))) → bc(cb(bb(bc(x1)))) (37)
ba(aa(ab(ba(x1)))) → bc(cb(bb(ba(x1)))) (38)
ba(aa(ab(bb(x1)))) → bc(cb(bb(bb(x1)))) (39)
cc(cc(cb(bc(x1)))) → cb(bc(cb(bc(x1)))) (40)
cc(cc(cb(ba(x1)))) → cb(bc(cb(ba(x1)))) (41)
cc(cc(cb(bb(x1)))) → cb(bc(cb(bb(x1)))) (42)
ac(cc(cb(bc(x1)))) → ab(bc(cb(bc(x1)))) (43)
ac(cc(cb(ba(x1)))) → ab(bc(cb(ba(x1)))) (44)
ac(cc(cb(bb(x1)))) → ab(bc(cb(bb(x1)))) (45)
bc(cc(cb(bc(x1)))) → bb(bc(cb(bc(x1)))) (46)
bc(cc(cb(ba(x1)))) → bb(bc(cb(ba(x1)))) (47)
bc(cc(cb(bb(x1)))) → bb(bc(cb(bb(x1)))) (48)
ca(ab(ba(ac(x1)))) → cc(cc(ca(ac(x1)))) (49)
ca(ab(ba(aa(x1)))) → cc(cc(ca(aa(x1)))) (50)
ca(ab(ba(ab(x1)))) → cc(cc(ca(ab(x1)))) (51)
aa(ab(ba(ac(x1)))) → ac(cc(ca(ac(x1)))) (52)
aa(ab(ba(aa(x1)))) → ac(cc(ca(aa(x1)))) (53)
aa(ab(ba(ab(x1)))) → ac(cc(ca(ab(x1)))) (54)
ba(ab(ba(ac(x1)))) → bc(cc(ca(ac(x1)))) (55)
ba(ab(ba(aa(x1)))) → bc(cc(ca(aa(x1)))) (56)
ba(ab(ba(ab(x1)))) → bc(cc(ca(ab(x1)))) (57)
cb(ba(aa(ac(x1)))) → ca(ab(bc(cc(x1)))) (58)
cb(ba(aa(aa(x1)))) → ca(ab(bc(ca(x1)))) (59)
cb(ba(aa(ab(x1)))) → ca(ab(bc(cb(x1)))) (60)
ab(ba(aa(ac(x1)))) → aa(ab(bc(cc(x1)))) (61)
ab(ba(aa(aa(x1)))) → aa(ab(bc(ca(x1)))) (62)
ab(ba(aa(ab(x1)))) → aa(ab(bc(cb(x1)))) (63)
bb(ba(aa(ac(x1)))) → ba(ab(bc(cc(x1)))) (64)
bb(ba(aa(aa(x1)))) → ba(ab(bc(ca(x1)))) (65)
bb(ba(aa(ab(x1)))) → ba(ab(bc(cb(x1)))) (66)

1.1.1.1 Rule Removal

Using the linear polynomial interpretation over the naturals
[cc(x1)] = 1 · x1
[ca(x1)] = 1 · x1
[aa(x1)] = 1 · x1
[ac(x1)] = 1 · x1
[cb(x1)] = 1 · x1
[ab(x1)] = 1 · x1
[bc(x1)] = 1 · x1
[bb(x1)] = 1 · x1
[ba(x1)] = 1 + 1 · x1
all of the following rules can be deleted.
ba(aa(ab(bc(x1)))) → bc(cb(bb(bc(x1)))) (37)
ba(aa(ab(ba(x1)))) → bc(cb(bb(ba(x1)))) (38)
ba(aa(ab(bb(x1)))) → bc(cb(bb(bb(x1)))) (39)
ca(ab(ba(ac(x1)))) → cc(cc(ca(ac(x1)))) (49)
ca(ab(ba(aa(x1)))) → cc(cc(ca(aa(x1)))) (50)
ca(ab(ba(ab(x1)))) → cc(cc(ca(ab(x1)))) (51)
aa(ab(ba(ac(x1)))) → ac(cc(ca(ac(x1)))) (52)
aa(ab(ba(aa(x1)))) → ac(cc(ca(aa(x1)))) (53)
aa(ab(ba(ab(x1)))) → ac(cc(ca(ab(x1)))) (54)
ba(ab(ba(ac(x1)))) → bc(cc(ca(ac(x1)))) (55)
ba(ab(ba(aa(x1)))) → bc(cc(ca(aa(x1)))) (56)
ba(ab(ba(ab(x1)))) → bc(cc(ca(ab(x1)))) (57)
cb(ba(aa(ac(x1)))) → ca(ab(bc(cc(x1)))) (58)
cb(ba(aa(aa(x1)))) → ca(ab(bc(ca(x1)))) (59)
cb(ba(aa(ab(x1)))) → ca(ab(bc(cb(x1)))) (60)
ab(ba(aa(ac(x1)))) → aa(ab(bc(cc(x1)))) (61)
ab(ba(aa(aa(x1)))) → aa(ab(bc(ca(x1)))) (62)
ab(ba(aa(ab(x1)))) → aa(ab(bc(cb(x1)))) (63)

1.1.1.1.1 Rule Removal

Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions
prec(cc) = 0 weight(cc) = 10
prec(ca) = 1 weight(ca) = 9
prec(aa) = 4 weight(aa) = 7
prec(ac) = 2 weight(ac) = 10
prec(cb) = 7 weight(cb) = 1
prec(ab) = 6 weight(ab) = 1
prec(bc) = 3 weight(bc) = 7
prec(bb) = 5 weight(bb) = 4
prec(ba) = 8 weight(ba) = 2
all of the following rules can be deleted.
cc(cc(cc(x1))) → ca(aa(ac(x1))) (25)
cc(cc(ca(x1))) → ca(aa(aa(x1))) (26)
cc(cc(cb(x1))) → ca(aa(ab(x1))) (27)
ca(ac(cc(x1))) → cc(ca(ac(x1))) (28)
ca(ac(ca(x1))) → cc(ca(aa(x1))) (29)
ca(ac(cb(x1))) → cc(ca(ab(x1))) (30)
ca(aa(ab(bc(x1)))) → cc(cb(bb(bc(x1)))) (31)
ca(aa(ab(ba(x1)))) → cc(cb(bb(ba(x1)))) (32)
ca(aa(ab(bb(x1)))) → cc(cb(bb(bb(x1)))) (33)
aa(aa(ab(bc(x1)))) → ac(cb(bb(bc(x1)))) (34)
aa(aa(ab(ba(x1)))) → ac(cb(bb(ba(x1)))) (35)
aa(aa(ab(bb(x1)))) → ac(cb(bb(bb(x1)))) (36)
cc(cc(cb(bc(x1)))) → cb(bc(cb(bc(x1)))) (40)
cc(cc(cb(ba(x1)))) → cb(bc(cb(ba(x1)))) (41)
cc(cc(cb(bb(x1)))) → cb(bc(cb(bb(x1)))) (42)
ac(cc(cb(bc(x1)))) → ab(bc(cb(bc(x1)))) (43)
ac(cc(cb(ba(x1)))) → ab(bc(cb(ba(x1)))) (44)
ac(cc(cb(bb(x1)))) → ab(bc(cb(bb(x1)))) (45)
bc(cc(cb(bc(x1)))) → bb(bc(cb(bc(x1)))) (46)
bc(cc(cb(ba(x1)))) → bb(bc(cb(ba(x1)))) (47)
bc(cc(cb(bb(x1)))) → bb(bc(cb(bb(x1)))) (48)
bb(ba(aa(ac(x1)))) → ba(ab(bc(cc(x1)))) (64)
bb(ba(aa(aa(x1)))) → ba(ab(bc(ca(x1)))) (65)
bb(ba(aa(ab(x1)))) → ba(ab(bc(cb(x1)))) (66)

1.1.1.1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.