Certification Problem

Input (TPDB SRS_Relative/Waldmann_19/random-115)

The relative rewrite relation R/S is considered where R is the following TRS

c(a(c(x1))) → c(c(b(x1))) (1)
c(c(c(x1))) → b(c(c(x1))) (2)

and S is the following TRS.

b(c(b(x1))) → b(c(b(x1))) (3)
b(c(a(x1))) → a(c(b(x1))) (4)
c(b(a(x1))) → c(a(a(x1))) (5)
a(b(a(x1))) → c(a(a(x1))) (6)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 Closure Under Flat Contexts

Using the flat contexts

{c(☐), a(☐), b(☐)}

We obtain the transformed TRS
c(a(c(x1))) → c(c(b(x1))) (1)
c(c(c(c(x1)))) → c(b(c(c(x1)))) (7)
a(c(c(c(x1)))) → a(b(c(c(x1)))) (8)
b(c(c(c(x1)))) → b(b(c(c(x1)))) (9)
c(b(a(x1))) → c(a(a(x1))) (5)
c(b(c(a(x1)))) → c(a(c(b(x1)))) (10)
a(b(c(a(x1)))) → a(a(c(b(x1)))) (11)
b(b(c(a(x1)))) → b(a(c(b(x1)))) (12)
c(a(b(a(x1)))) → c(c(a(a(x1)))) (13)
a(a(b(a(x1)))) → a(c(a(a(x1)))) (14)
b(a(b(a(x1)))) → b(c(a(a(x1)))) (15)

1.1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
ca(ac(cc(x1))) → cc(cb(bc(x1))) (16)
ca(ac(ca(x1))) → cc(cb(ba(x1))) (17)
ca(ac(cb(x1))) → cc(cb(bb(x1))) (18)
cc(cc(cc(cc(x1)))) → cb(bc(cc(cc(x1)))) (19)
cc(cc(cc(ca(x1)))) → cb(bc(cc(ca(x1)))) (20)
cc(cc(cc(cb(x1)))) → cb(bc(cc(cb(x1)))) (21)
ac(cc(cc(cc(x1)))) → ab(bc(cc(cc(x1)))) (22)
ac(cc(cc(ca(x1)))) → ab(bc(cc(ca(x1)))) (23)
ac(cc(cc(cb(x1)))) → ab(bc(cc(cb(x1)))) (24)
bc(cc(cc(cc(x1)))) → bb(bc(cc(cc(x1)))) (25)
bc(cc(cc(ca(x1)))) → bb(bc(cc(ca(x1)))) (26)
bc(cc(cc(cb(x1)))) → bb(bc(cc(cb(x1)))) (27)
cb(ba(ac(x1))) → ca(aa(ac(x1))) (28)
cb(ba(aa(x1))) → ca(aa(aa(x1))) (29)
cb(ba(ab(x1))) → ca(aa(ab(x1))) (30)
cb(bc(ca(ac(x1)))) → ca(ac(cb(bc(x1)))) (31)
cb(bc(ca(aa(x1)))) → ca(ac(cb(ba(x1)))) (32)
cb(bc(ca(ab(x1)))) → ca(ac(cb(bb(x1)))) (33)
ab(bc(ca(ac(x1)))) → aa(ac(cb(bc(x1)))) (34)
ab(bc(ca(aa(x1)))) → aa(ac(cb(ba(x1)))) (35)
ab(bc(ca(ab(x1)))) → aa(ac(cb(bb(x1)))) (36)
bb(bc(ca(ac(x1)))) → ba(ac(cb(bc(x1)))) (37)
bb(bc(ca(aa(x1)))) → ba(ac(cb(ba(x1)))) (38)
bb(bc(ca(ab(x1)))) → ba(ac(cb(bb(x1)))) (39)
ca(ab(ba(ac(x1)))) → cc(ca(aa(ac(x1)))) (40)
ca(ab(ba(aa(x1)))) → cc(ca(aa(aa(x1)))) (41)
ca(ab(ba(ab(x1)))) → cc(ca(aa(ab(x1)))) (42)
aa(ab(ba(ac(x1)))) → ac(ca(aa(ac(x1)))) (43)
aa(ab(ba(aa(x1)))) → ac(ca(aa(aa(x1)))) (44)
aa(ab(ba(ab(x1)))) → ac(ca(aa(ab(x1)))) (45)
ba(ab(ba(ac(x1)))) → bc(ca(aa(ac(x1)))) (46)
ba(ab(ba(aa(x1)))) → bc(ca(aa(aa(x1)))) (47)
ba(ab(ba(ab(x1)))) → bc(ca(aa(ab(x1)))) (48)

1.1.1 Rule Removal

Using the Knuth Bendix order with w0 = 1 and the following precedence and weight functions
prec(ca) = 3 weight(ca) = 5
prec(ac) = 5 weight(ac) = 1
prec(cc) = 0 weight(cc) = 4
prec(cb) = 6 weight(cb) = 4
prec(bc) = 1 weight(bc) = 2
prec(ba) = 2 weight(ba) = 3
prec(bb) = 7 weight(bb) = 2
prec(ab) = 4 weight(ab) = 3
prec(aa) = 8 weight(aa) = 2
all of the following rules can be deleted.
ca(ac(cc(x1))) → cc(cb(bc(x1))) (16)
ca(ac(ca(x1))) → cc(cb(ba(x1))) (17)
ca(ac(cb(x1))) → cc(cb(bb(x1))) (18)
cc(cc(cc(cc(x1)))) → cb(bc(cc(cc(x1)))) (19)
cc(cc(cc(ca(x1)))) → cb(bc(cc(ca(x1)))) (20)
cc(cc(cc(cb(x1)))) → cb(bc(cc(cb(x1)))) (21)
ac(cc(cc(cc(x1)))) → ab(bc(cc(cc(x1)))) (22)
ac(cc(cc(ca(x1)))) → ab(bc(cc(ca(x1)))) (23)
ac(cc(cc(cb(x1)))) → ab(bc(cc(cb(x1)))) (24)
bc(cc(cc(cc(x1)))) → bb(bc(cc(cc(x1)))) (25)
bc(cc(cc(ca(x1)))) → bb(bc(cc(ca(x1)))) (26)
bc(cc(cc(cb(x1)))) → bb(bc(cc(cb(x1)))) (27)
cb(ba(ac(x1))) → ca(aa(ac(x1))) (28)
cb(ba(aa(x1))) → ca(aa(aa(x1))) (29)
cb(ba(ab(x1))) → ca(aa(ab(x1))) (30)
cb(bc(ca(ac(x1)))) → ca(ac(cb(bc(x1)))) (31)
cb(bc(ca(aa(x1)))) → ca(ac(cb(ba(x1)))) (32)
cb(bc(ca(ab(x1)))) → ca(ac(cb(bb(x1)))) (33)
ab(bc(ca(ac(x1)))) → aa(ac(cb(bc(x1)))) (34)
ab(bc(ca(aa(x1)))) → aa(ac(cb(ba(x1)))) (35)
ab(bc(ca(ab(x1)))) → aa(ac(cb(bb(x1)))) (36)
bb(bc(ca(ac(x1)))) → ba(ac(cb(bc(x1)))) (37)
bb(bc(ca(aa(x1)))) → ba(ac(cb(ba(x1)))) (38)
bb(bc(ca(ab(x1)))) → ba(ac(cb(bb(x1)))) (39)
ca(ab(ba(ac(x1)))) → cc(ca(aa(ac(x1)))) (40)
ca(ab(ba(aa(x1)))) → cc(ca(aa(aa(x1)))) (41)
ca(ab(ba(ab(x1)))) → cc(ca(aa(ab(x1)))) (42)
aa(ab(ba(ac(x1)))) → ac(ca(aa(ac(x1)))) (43)
aa(ab(ba(aa(x1)))) → ac(ca(aa(aa(x1)))) (44)
aa(ab(ba(ab(x1)))) → ac(ca(aa(ab(x1)))) (45)
ba(ab(ba(ac(x1)))) → bc(ca(aa(ac(x1)))) (46)
ba(ab(ba(aa(x1)))) → bc(ca(aa(aa(x1)))) (47)
ba(ab(ba(ab(x1)))) → bc(ca(aa(ab(x1)))) (48)

1.1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.